[Challenge/Puzzle][Very Hard] Industrial Trap

How to make a very^C lunatic* level: Find an enemy that goes either left or right randomly upon entering the screen. Create a screen so that if they go left you die, and if they go right, you pass through. Copy-pasta 100 of those screens in a row:

*where C is a constant

How to make a very^C lunatic* level: Find an enemy that goes either left or right randomly upon entering the screen. Create a screen so that if they go left you die, and if they go right, you pass through. Copy-pasta 100 of those screens in a row:

*where C is a constant

Only a 1 in 1,267,650,600,228,229,401,496,703,205,376 chance of beating that.

Let's see now. The average person can tackle a hard screen in 10 tries? Perhaps an easy one in 1. That means *10 every two levels of difficult increased. By that logic, [Level of difficulty] = [Easy][Harder]^{2log₁₀[# of attempts/screen]}

So, 10 tries = easy * harder * harder = hard
1,267,650,600,228,229,401,496,703,205,376, or 2¹⁰⁰, tries would be:

[Easy][Harder]2log10(2100).	= [Easy][Harder]200log10(2)
	= [Easy][Harder]200log10(2) - 4 + 4
	= [Easy][Harder]4[Harder]200log10(2) - 4
	= [Lunatic][Harder]200log10(2) - 4
	= [Very]200log10(2) - 4[Lunatic]

So.. anyone wanna whip out their calculator and find out what 200log₁₀(2) - 4 is?

About 56.206.

So approximately very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very lunatic.
[/offtopic discussion]

Secret Glitch, I would like you to make a Safety 3

Secret Glitch, I would like you to make a Safety 3

Currently you are the only one.